Hi,
I have a question to carbonate ion (CO3--).
The calculated pH value is 11, TIC = 8 mg/l, alkalinity = 146 mg/l. CE-QUAL calculates the following carbonat spezies:
CO2 = 0 mg/l
HCO3- = 0,7 mg/l
CO3-- = 0 mg/l
At a pH value of 11 TIC has to be existent as CO3--. Why is the carbonate ion 0? And whereto is the TIC of 7,3 mg/l (=8 - 0,7) lost?
Can anybody help me?
With many regards
Michaela